15) C

Every team will play two matches against the other 5 teams in their pools. We must use the following process:

A plays B,C,D,E,F twice – 10 matches
B plays C,D,E,F twice – 8 matches
C plays D,E,F twice – 6 matches
D plays E,F twice – 4 matches
E plays F twice – 2 matches
SUM – 10 + 8 + 6 + 4 + 2= 30 matches in one pool

This gives a total of 60 matches in 2 pools. Since each team plays each of the other teams in other pool once, this gives us 6 x 6 = 36 matches. Finally, there is the final which is 1 match.
Total number of matches: 60 + 36 + 1 = 97 matches

Leave a Reply