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2003 Section 2 Question 9

9) B

n(H₂) = 9/2 = 4.5 moles
n(N₂) = 56/28 = 2 moles

Ratio of H₂:NH₃ = 3:2
4.5 moles of Hydrogen reacts with 3 moles of Ammonia

We then use the formula:
moles = mass/Mr
moles = 3
mass = unknown
Mr = 14 + 3 = 17

moles = m/Mr
m = moles x Mr = 3 x 17 = 51 grams

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