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2008 Section 2 Question 8

8) A

Speed of lift = 0.4 m/s
Time the load is lifted for = 5s
Distance (height above ground) = 0.4 x 5 = 2 m

Potential energy = m x g x h = 100 x 10 x 2 = 2000J
Hence statement 1 is correct.

In order to lift the load the tension in the cable at point P must be equal to the weight of the load.
Weight of the load = 100 x 10 = 1000N
Hence tension at P = 1000N
So statement 2 is wrong.

The question states that the load is being lifted at a constant speed. This means that there is not change in speed. So there is no acceleration at all.

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