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2010 Section 1 Question 16

16) D

This can only be solved by visualisation. 

We can eliminate A and C easily though. Look at the original die. The orientation between 5 and 6 is different in the original die as compared to A and C. 

B has the same orientation of 3 as it is in the original die. This is only possible when the die is rotated in the same direction twice. Since it was rotated in a different direction, B is worn.g 

In E, none of the original numbers are present on the die. At least one of the original number should have remained after 2 rotations, no matter the direction. So E is wrong.

We are left with D. 

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