10) F

This is a simple addition question.

No. of N = 2

Mass number of N = 14

Total mass of N = (14 x 2) = 28

No. of H = 20

Mass number of H = 1

Total mass of H = (20 x 1) = 20

No. of Fe = 1

Mass number of Fe = 56

Total mass of Fe = (56 x 1) = 56

No. of S = 2

Mass number of S = 32

Total mass of nitrogen = (32 x 2) = 64

No. of O = 14

Mass number of O = 16

Total mass of nitrogen = (16 x 14) = 224

Now, we add all of these values together = 28 + 20 + 56 + 64 + 224 = 392

The answer is F.

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