27) C

We know that KE = 0.5mv²

We first need to find out whether the graph will go through zero or not.

Using the eqaution above, we can see that if v² = 0, then K.E. will also be equal to 0.

So the graph does go through 0,0.

y = mx + c

Since c (y-intercept) = 0, we get the equation,

y = mx

K.E. = 0.5 mv²

We know the K.E. is on the y-axis and the square of speed is on the x-axis.

Therefore, m (gradient) in the equation (y = mx) would be 0.5 m (0.5 mass).

We know that the mass = 2.5 kg

So gradient = 0.5 x 2.5 = 1.25

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