29) C

Let die with 0 to 5 spots be die X.
Let die with 2 to 7 spots be die Y.

In the diagram of the two dice shown together, the left die is die Y. We can come to this conclusion because 3 and 2 are adjacent to each other, which cannot happen in the die, which has 0 to 5 spots. So the right die is X.

A cannot be the answer. One of the faces of die in option A has 6 spots so it cannot be die X. It cannot be die Y because opposite faces must add up to 9 which means 6 must be opposite 3. In option A, however, 6 and 3 are adjacent.

B cannot be the answer. It cannot be X because 3 is adjacent to 2. It cannot be Y because if you try and align faces of die in option B exactly as it is in the picture of Y, you will realise that face with 3 spots swaps with the face with 2 spots.

D cannot be the answer. It cannot be X as one of its faces has 6 spots. It also cannot be Y. This requires good spatial visualisation skills. Let me try and explain. In the picture of Y (left die), one spot of 3, one spot of 2 and one spot of 5 all meet at one vertex (point of a cube). If you try and align die in option D as it is in the pic of Y, you will realise this does not happen. The following picture is a picture of what die in option D would look like. If you compare the following picture with the picture of Y, you will realise that D is not correct.

E cannot be the answer. It cannot be Y because 5 and 4 are adjacent to each other. It cannot be X because if you aligned die in option E as it is in pic of X (with 4 as top face), you will realise that in option E, 3 is in place of 2. So E is wrong.