You have come across mean throughout your academics. It is a simple concept of finding the average of a set of data.

In the BMAT exam, however, the question is twisted around to confuse the candidates.

Therefore, it is important to brush up on the basics. I created a sample complicated question to give you an idea of how the question can be twisted around.

My advice is to use the information to calculate anything that you can. Then go from there.

A basic question:

Example:
There are three students in Further Maths in Year 12. Their scores in a test are 45, 49 and 52. What is the mean score?

Solution:
We add the scores together first. We get:
45 + 49 + 52 = 146

Then, we divide it by the number of students, i.e. 3
146 ÷ 3 = 48.666 ≈ 48.7

Complicated Question
There are ‘P’ number of people in a group. They have a mean weight of 50 kg.
The number of people in the group increases by 20 and the mean weight decreases by 2 kg.
Create a formula for mean weight of the second group.

Solution:

First Step
Find the mean weight of the second group.
We are told that the mean weight decreases by 2 kg.
So mean weight = 50 – 2 = 48 kg.

Second Step
Find the number of people in the second group.
We are told that the number of people increases by 20.
So number of people in second group = P + 20

Third Step
Find the sum of the weights of people in the second group.
We can simply do this by multiplying the mean weight (48) with the number of people (P + 20).
Total weight of people in second group = 48 (P + 20) = (48P + 960) kg

Fourth Step
Create a formula for the mean weight (48 kg).
Mean weight = total weight ÷ total number of people
48 = (48P + 960) ÷ (P + 20)